A recursive approach (which is what I would use) would involve breaking the problem into isomorphic subproblems: to find all permutations of a string, find all permutations of the string without a ...

def perms(s, temp): """s is a string, temp is part of the output found so far.""" if len(s) == 0: print temp return for i in s: s2 = s.replace(i, '') temp += i perms ...

Hi everyone,<BR><BR>Let's say I have 4 numbers: 1234.<BR><BR>I wish to find out all possible permutations of this 4 numbers. I believe there is a total of 12 permutations.<BR><BR>I couldnt figure out ...